Saturday, July 4, 2015

Segment Tree Query I II

Medium Segment Tree Query

34%
Accepted
For an integer array (index from 0 to n-1, where n is the size of this array), in the corresponding SegmentTree, each node stores an extra attribute max to denote the maximum number in the interval of the array (index from start to end).
Design a query method with three parameters rootstartand end, find the maximum number in the interval [start, end] by the given root of segment tree.
Have you met this question in a real interview? 
Yes
Example
For array [1, 4, 2, 3], the corresponding Segment Tree is:
                  [0, 3, max=4]
                 /             \
          [0,1,max=4]        [2,3,max=3]
          /         \        /         \
   [0,0,max=1] [1,1,max=4] [2,2,max=2], [3,3,max=3]
query(root, 1, 1), return 4
query(root, 1, 2), return 4
query(root, 2, 3), return 3
query(root, 0, 2), return 4
Note
It is much easier to understand this problem if you finished Segment Tree Build first.

/**
 * Definition of SegmentTreeNode:
 * public class SegmentTreeNode {
 *     public int start, end, max;
 *     public SegmentTreeNode left, right;
 *     public SegmentTreeNode(int start, int end, int max) {
 *         this.start = start;
 *         this.end = end;
 *         this.max = max
 *         this.left = this.right = null;
 *     }
 * }
 */
public class Solution {
    /**
     *@param root, start, end: The root of segment tree and 
     *                         an segment / interval
     *@return: The maximum number in the interval [start, end]
     */
    public int query(SegmentTreeNode root, int start, int end) {
        // write your code here
        if(root == null || root.start > end || root.end < start) return 0;
        if(root.start == root.end) return root.max;
        return Math.max(query(root.left, start, end), query(root.right, start, end));
    }
}

II===>


For an array, we can build a SegmentTree for it, each node stores an extra attribute count to denote the number of elements in the the array which value is between interval start and end. (The array may not fully filled by elements)
Design a query method with three parameters rootstartand end, find the number of elements in the in array's interval [startend] by the given root of value SegmentTree.
Have you met this question in a real interview? 
Yes
Example
For array [0, 2, 3], the corresponding value Segment Tree is:
                     [0, 3, count=3]
                     /             \
          [0,1,count=1]             [2,3,count=2]
          /         \               /            \
   [0,0,count=1] [1,1,count=0] [2,2,count=1], [3,3,count=1]
query(1, 1), return 0
query(1, 2), return 1
query(2, 3), return 2
query(0, 2), return 2
Note
It is much easier to understand this problem if you finished Segment Tree BuildandSegment Tree Query first.
Tags Expand  

//**
 * Definition of SegmentTreeNode:
 * public class SegmentTreeNode {
 *     public int start, end, count;
 *     public SegmentTreeNode left, right;
 *     public SegmentTreeNode(int start, int end, int count) {
 *         this.start = start;
 *         this.end = end;
 *         this.count = count;
 *         this.left = this.right = null;
 *     }
 * }
 */
public class Solution {
    /**
     *@param root, start, end: The root of segment tree and
     *                         an segment / interval
     *@return: The count number in the interval [start, end]
     */
    public int query(SegmentTreeNode root, int start, int end) {
        // write your code here
         if(root == null || root.start > end || root.end < start) return 0;
        if(root.start == root.end) return root.count;
        return query(root.left, start, end)+ query(root.right, start, end);
    }
}



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