The structure of Segment Tree is a binary tree which each node has two attributes
start
and end
denote an segment / interval.
start and end are both integers, they should be assigned in following rules:
- The root's start and end is given by
build
method. - The left child of node A has
start=A.left, end=(A.left + A.right) / 2
. - The right child of node A has
start=(A.left + A.right) / 2 + 1, end=A.right
. - if start equals to end, there will be no children for this node.
Implement a
Have you met this question in a real interview? build
method with two parameters start and end, so that we can create a corresponding segment tree with every node has the correct start and end value, return the root of this segment tree.
Yes
Example
Given
start=0, end=3
. The segment tree will be: [0, 3]
/ \
[0, 1] [2, 3]
/ \ / \
[0, 0] [1, 1] [2, 2] [3, 3]
Given
start=1, end=6
. The segment tree will be: [1, 6]
/ \
[1, 3] [4, 6]
/ \ / \
[1, 2] [3,3] [4, 5] [6,6]
/ \ / \
[1,1] [2,2] [4,4] [5,5]
Clarification
Segment Tree (a.k.a Interval Tree) is an advanced data structure which can support queries like:
- which of these intervals contain a given point
- which of these points are in a given interval
See wiki: Segment Tree Interval Tree
/**
* Definition of SegmentTreeNode:
* public class SegmentTreeNode {
* public int start, end;
* public SegmentTreeNode left, right;
* public SegmentTreeNode(int start, int end) {
* this.start = start, this.end = end;
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/**
*@param start, end: Denote an segment / interval
*@return: The root of Segment Tree
*/
public SegmentTreeNode build(int start, int end) {
// write your code here
if(start > end) return null;
if(start == end) return new SegmentTreeNode(start, end);
SegmentTreeNode root = new SegmentTreeNode(start, end);
root.left = build(start, (start+end)/2);
root.right = build((start+end)/2+1, end);
return root;
}
}
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