For a
Maximum Segment Tree
, which each node has an extra value max
to store the maximum value in this node's interval.
Implement a
Have you met this question in a real interview? modify
function with three parameter root
,index
and value
to change the node's value with [start, end] = [index, index] to the new given value. Make sure after this change, every node in segment tree still has the max attribute with the correct value.
Yes
Example
For segment tree:
[1, 4, max=3]
/ \
[1, 2, max=2] [3, 4, max=3]
/ \ / \
[1, 1, max=2], [2, 2, max=1], [3, 3, max=0], [4, 4, max=3]
if call
modify(root, 2, 4)
, we can get: [1, 4, max=4]
/ \
[1, 2, max=4] [3, 4, max=3]
/ \ / \
[1, 1, max=2], [2, 2, max=4], [3, 3, max=0], [4, 4, max=3]
or call
modify(root, 4, 0)
, we can get: [1, 4, max=2]
/ \
[1, 2, max=2] [3, 4, max=0]
/ \ / \
[1, 1, max=2], [2, 2, max=1], [3, 3, max=0], [4, 4, max=0]
Note
We suggest you finish problem Segment Tree Build and Segment Tree Query first.
Challenge
Do it in
O(h)
time, h is the height of the segment tree.
/**
* Definition of SegmentTreeNode:
* public class SegmentTreeNode {
* public int start, end, max;
* public SegmentTreeNode left, right;
* public SegmentTreeNode(int start, int end, int max) {
* this.start = start;
* this.end = end;
* this.max = max
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/**
*@param root, index, value: The root of segment tree and
*@ change the node's value with [index, index] to the new given value
*@return: void
*/
public void modify(SegmentTreeNode root, int index, int value) {
// write your code here
if(root == null || root.start > index || root.end < index) return;
if(root.start == root.end) {
root.max = value;
return;
}
int mid = (root.start + root.end) / 2;
if(mid + 1 <= index){
modify(root.right, index, value);
} else {
modify(root.left, index, value);
}
root.max = Math.max(root.left.max, root.right.max);
}
}
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