Given a linked list, remove the nth node from the end of list and return its head.
Have you met this question in a real interview?
Yes
Example
Given linked list: 1->2->3->4->5->null, and n = 2.
After removing the second node from the end, the linked list becomes 1->2->3->5->null.
Note
The minimum number of nodes in list is n.
Challenge
O(n) time
/**
* Definition for ListNode.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int val) {
* this.val = val;
* this.next = null;
* }
* }
*/
public class Solution {
/**
* @param head: The first node of linked list.
* @param n: An integer.
* @return: The head of linked list.
*/
ListNode removeNthFromEnd(ListNode head, int n) {
// write your code here
if(head == null || n <= 0) return head;
ListNode node = head;
for(int i = 0; i < n; i++){
if(node == null) return null;
node = node.next;
}
ListNode dummy = new ListNode(0);
dummy.next = head;
ListNode preDelete = dummy;
while(node != null){
node = node.next;
preDelete = preDelete.next;
}
preDelete.next = preDelete.next.next;
return dummy.next;
}
}
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