Sort a linked list using insertion sort.
Have you met this question in a real interview?
Yes
Example
Given
1->3->2->0->null
, return0->1->2->3->null
.
/**
* Definition for ListNode.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int val) {
* this.val = val;
* this.next = null;
* }
* }
*/
public class Solution {
/**
* @param head: The first node of linked list.
* @return: The head of linked list.
*/
public ListNode insertionSortList(ListNode head) {
// write your code here
ListNode dummy = new ListNode(Integer.MIN_VALUE);
while(head != null){
ListNode node = dummy;
while(node.next != null && node.next.val < head.val) node = node.next;
ListNode temp = head.next;
head.next = node.next;
node.next = head;
head = temp;
}
return dummy.next;
}
}
No comments:
Post a Comment