Given a non-overlapping interval list which is sorted by start point.
Insert a new interval into it, make sure the list is still in order and non-overlapping (merge intervals if necessary).
Have you met this question in a real interview?
Yes
Example
Insert [2, 5] into [[1,2], [5,9]], we get [[1,9]].
Insert [3, 4] into [[1,2], [5,9]], we get [[1,2], [3,4], [5,9]].
class Solution {
/**
* Insert newInterval into intervals.
* @param intervals: Sorted interval list.
* @param newInterval: A new interval.
* @return: A new sorted interval list.
*/
public ArrayList<Interval> insert(ArrayList<Interval> intervals, Interval newInterval) {
ArrayList<Interval> result = new ArrayList<Interval>();
// write your code here
for(Interval interval : intervals){
if(interval.end < newInterval.start){
result.add(interval);
} else if(interval.start > newInterval.end){
result.add(newInterval);
newInterval = interval;
} else if(interval.end >= newInterval.start || interval.start <= newInterval.end){
newInterval.start = Math.min(newInterval.start, interval.start);
newInterval.end = Math.max(newInterval.end, interval.end);
}
}
result.add(newInterval);
return result;
}
}
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