Write an efficient algorithm that searches for a value in an m x n matrix, return the occurrence of it.
This matrix has the following properties:
* Integers in each row are sorted from left to right.
* Integers in each column are sorted from up to bottom.
* No duplicate integers in each row or column.
Have you met this question in a real interview?
Yes
Example
Consider the following matrix:
[
[1, 3, 5, 7],
[2, 4, 7, 8],
[3, 5, 9, 10]
]
Given target = 3, return 2.
Challenge
O(m+n) time and O(1) extra space
public class Solution {
/**
* @param matrix: A list of lists of integers
* @param: A number you want to search in the matrix
* @return: An integer indicate the occurrence of target in the given matrix
*/
public int searchMatrix(int[][] matrix, int target) {
// write your code here
if(matrix == null || matrix.length == 0 || matrix[0].length == 0){
return 0;
}
int m = matrix.length, n = matrix[0].length;
int count = 0;
int i = 0, j = n - 1;
while(i < m && j >= 0){
if(matrix[i][j] == target){
count++;
i++;
j--;
} else if(matrix[i][j] > target){
j--;
} else {
i++;
}
}
return count;
}
}
No comments:
Post a Comment